A fast decay

At the highest energy levels and without external forces,

it seems likely that the decay occurs at the very first "opportunity",

let's say at a node of the very first oscillation.

The reply by Gemini-Bard 1.5:

The idea that a highly energetic string might decay at the node of its first oscillation is an interesting one, but it's important to understand that:

String Decay is Complex: String decay in string theory is a highly complex process. It's not simply a matter of a string "breaking" at a point of minimal vibration.
No Simple Analogy: While the concept of a node in a wave is relevant, string theory operates in higher dimensions and involves intricate quantum interactions. There's no direct, simple analogy to a classical string breaking at a node.
Quantum Fluctuations: At the highest energy levels, quantum fluctuations and uncertainties become significant. These fluctuations could influence the decay process in ways that aren't easily predictable based on classical intuition.

Possible Decay Mechanisms (Hypothetical):

Emission of Particles: A highly energetic string might decay by emitting other particles (like gravitons, photons, or other fundamental particles) as it transitions to a lower energy state.
String Interactions: Interactions between strings could lead to decay processes, where energy and momentum are exchanged between them.
Black Hole Formation: At extremely high energies, the string might collapse into a microscopic black hole, which would then evaporate through Hawking radiation.

Important Note:

String Theory is Still Under Development: Our understanding of string decay is still an area of active research. Many aspects of string theory, including decay mechanisms, are not fully understood.

In Summary:

While the idea of decay at a node is intriguing, it's likely an oversimplification of the complex processes involved in string decay. Further research and theoretical developments are needed to fully understand these phenomena.

Disclaimer:

This information is for general knowledge and educational purposes only.
String theory is a highly specialized and evolving field of physics.

My reply:

Would the wave phenomenon probably interrupt

and decay at a quarter of a spatial wave from the completely symmetric corpuscle

until the formation of what could be visually represented as a first spatial node?

The reply by Gemini-Bard 1.5:

The idea that a highly energetic string might decay at a specific point along its vibrational wave, such as a quarter wavelength from a symmetrical point, is a fascinating one, but it's important to understand that:

String Theory is Complex: String theory operates in higher dimensions, and the dynamics of string vibrations are far more intricate than those of a simple classical string.
No Simple Analogy: While the concept of a wavelength and nodes is relevant in classical wave phenomena, its direct application to string decay is not straightforward.
Quantum Effects Dominate: At the high energy levels relevant to string theory, quantum effects play a crucial role. These quantum effects, such as quantum fluctuations and uncertainties, can significantly influence the decay process in ways that are not easily predictable based on classical wave behavior.

Key Points:

String Decay Mechanisms: String decay likely involves complex interactions and emissions of particles, as discussed earlier.
No Guaranteed Decay Point: There's no reason to believe that a string will preferentially decay at a specific point along its vibrational wave, such as a quarter wavelength.
Focus on Research: Understanding string decay is an active area of research in string theory.

In Summary:

While the concept of a quarter wavelength might seem relevant, it's likely an oversimplification of the complex processes involved in string decay.

Disclaimer:

This information is for general knowledge and educational purposes only.
String theory is a highly specialized and evolving field of physics.

I hope this clarifies some of the complexities involved in considering string decay!